Question 313704
The length of a rectangle is 4m greater than the width. The area of the rectangle is {{{96 m^2}}}. What is the length and the width of the rectangle?

Let x = length of the rectangle
    y = width of the rectangle
Representation : 
    x = y + 4
    Formula of the area of a rectangle A = lw therefore, A= xy
Solution: 
    A = {{{96m^2}}}
    96 = y (y + 4)
    96 = {{{y^2 + 4y}}}
     0 = {{{y^2 + 4y - 96}}}
     0 = (y + 12) (y - 8)
     0 = y + 12  |  0 = y - 8
     y = -12     |  y = 8
length and width should not be negative.. the answer for the width is 8m. Length is 4m greater than the width so 8 + 4 = 12m for the length. 

answer :
x = 12m and y = 8m