Question 313667
log(5x-1) + log(x+2)=1
log(5x-1)(x+2)=1
(5x-1)(x+2)=10^1
5x^2+10x-x-2 = 10
5x^2+9x-2 = 10
Use the quadratic formula to get our solutions:
x = {0.892, -2.692}
Checking for extraneous solutions we see that we can throw out the negative solution leaving:
x = 0.892
.
Details of quadratic follows:
*[invoke quadratic "x", 5, 9, -12 ]