Question 313670
{{{ (x+1)(x-5) = 16}}}
{{{ x^2-4x-5= 16}}}
{{{x^2-4x-21=0}}}
{{{(x-7)(x+3)=0}}}
Two solutions:
{{{x-7=0}}}
{{{highlight( x=7)}}}
.
.
.
{{{x+3=0}}}
{{{highlight( x=-3)}}}