Question 313179
{{{ (2q)/(2q+3)-(2q)/(2q-3)=1}}}
{{{(2q)(2q-3)-(2q)(2q+3)=(2q-3)(2q+3)}}}
{{{(2q)(2q-3-2q-3)=(2q-3)(2q+3)}}}
{{{(2q)(-6)=4q^2-9}}}
{{{-12q=4q^2-9}}}
{{{4q^2+12q-9=0}}}
Use the quadratic formula,
 {{{q = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{q = (-12 +- sqrt( 12^2-4*4*(-9) ))/(2*4) }}}
{{{q = (-12 +- sqrt( 144+144))/(8) }}}
{{{q = (-12 +- sqrt( 2(144)))/(8) }}}
{{{q = (-12 +- 12sqrt(2))/(8) }}}
{{{highlight(q = (-3 +- 3sqrt(2))/(2)) }}}