Question 313312
{{{ a=1 }}}
{{{b=4}}}
{{{c=-7}}}
{{{D=b^2-4ac}}}
{{{D=16-4(1)(-7)}}}
{{{D=44}}}
Since {{{D>0}}}, there will be two different solutions. 
Since {{{44}}} is not a perfect square, the solutions will be irrational.