Question 313270
Use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x, and use the resulting points to graph the function.
f(x) = 1/4x^2
:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
in the this equation, a = .25, b & c = 0
{{{x = (-0 +- sqrt( 0-4*.25*0 ))/(2*.25) }}}
x = {{{0/.5}}}
x = 0 obviously
then
y = 0
{{{ graph( 200, 200, -6, 5, -10, 10, .5x^2) }}}
:
Note the y intercept = 0, vertex 0,0 
:
"Then evaluate the function for several values of x, and use the resulting points to graph the function.
:
substitute for x in {{{1/4}}}x^2, find y
example,x=2: 
y = {{{1/4}}}2^2
y = 1
:
 x | y
-------
-2 |+1
-1 |+.25
 0 | 0
+1 |+.25
+2 |+1