Question 313271
Hello, 
Let the width be x and the length be x+1. Now we can use the Pythagorean formula:
a^2+b^2=c^2 Plug in what we have:
x^2+(x+1)^2= (sq rt3)^2 This can be rewritten as:
2x^2+2x+1=3 Subtract 3 from both sides to get:
2x^2+2x-2=0 From here we need to use the quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} Plug in the numbers:
x = -2 +- sqrt( 4+16)/(4) So we come up with 2 answers for x being:
x=.62 (approx)
x=-6.47 (approx) The negative doesn't make sense in our problem so .62 is the length of one side and 1.62 is the length of the other.
Make sense?
RJ www.math-unlock.com