Question 313271
let the width be x feet
the length will be x+1 feet
the diagonal is sqrt 3
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They form a right angle
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sqrt3 ^2 = x^2+(x+1)^2
3=x^2+x^2+2x+1
2x^2+2x-2 =0
x^2+x-1=0
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find the roots of the equation .
x1= (-1 + (sqrt1+4)) /2
x1=0.61
x2=(-1 - (sqrt1+4)) /2
x2= -1.61
width = 0.61 feet
Length will be 1+0.62 = 1.61 feet.