Question 313262
let the length of the pool be x yards
the width will be x-8
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The area of rectangje = L*W
x(x-8)=200
x^2-8x=200
x^2-8x-200=0
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x1, x2 the roots of the equation will be:
x1 = (8+sqrt(64+800)) / 2a
x1=18.7 yards
x2 =(8-sqrt(64+800)) / 2a
= -10.7 it is negative.
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SO the dimensions are 18.7 & 10.7 yards