Question 313091
{{{Y=(x-1)(x-5)}}}

{{{x^2-x-5x+5}}}
When you FOIL it will be
 x^2 - 5x - x + 5, (essentially the same as you had)
then combining the middle terms
{{{x^2 - 6x + 5}}}

x=-2

{{{(-2)^2 -6(-2) + 5 = Y}}}
{{{4 + 12 + 5 = Y}}}

y = 21

vertex=(-2,21)
This is not the vertex, just an ordered pair
:
To find the vertex, find the axis of symmetry, x = -b/(2a); b=-6; a=1
x = {{{(-(-6))/(2*1)}}}
x = {{{6/2}}}
x = 3 is the axis of symmetry
Find the value of y using x=3
y = 3^2 - 6(3) + 5
y = 9 - 18 + 5
y = -4
:
The vertex: 3,-4
:
Looks like this:
{{{ graph( 300, 200, -6, 10, -10, 10, x^2-6x+5) }}}