Question 36403
1) (2x)^2 * (3x^4)
{{{ 2^2*x^2*3*x^4}}}
{{{ 4x^2 *3x^4}}}


Remember when you multiply, you ADD exponents:
{{{12x^6}}} 

The answer is B. 



2) (-3x / 2y^3)^-2 
{{{ ((-3x)/(2y^3))^-2}}}


When you raise a fraction to a negative power, you invert the fraction.  When you raise a fraction to the 2 power you square the fraction.  This means that in raising to the -2 power, you must invert and square:
{{{((2y^3)/(-3x))^2 }}}

{{{(4y^6)/(9x^2))}}}


The correct answer is C


R^2 at SCC