Question 312911
Use the quadratic formula to determine the x-intercepts (if any) of the following function. Then evaluate the function for several values of x, and use the resulting points to graph the function.
f(x) = 1/2x^2
But why would you use the quadratic formula to find the intercepts
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
in the this equation, b & c = 0
{{{x = (-0 +- sqrt( 0-4*.5*0 ))/(2*.5) }}}
x = {{{0/1}}}
x = 0 obviously
then
y = 0
{{{ graph( 200, 200, -6, 5, -10, 10, .5x^2) }}}
:
"Then evaluate the function for several values of x, and use the resulting points to graph the function.
:
 x | y
-------
-2 |+2
-1 |+.5
 0 | 0
+1 |+.5
+2 |+2