Question 312985
{{{ graph( 300, 300, -5, 5, -10, 10, x^3+2x^2-4) }}}
I used Newton's method,
x(n+1)=x(n)-f(x(n))/f'(x(n))
with a starting value of {{{x0=1}}} and got a value of {{{x=1.130395}}} after 3 iterations.