Question 312867
Let {{{c}}} = number of coins
Let {{{b}}} = number of bills
given:
(1) {{{c + b = 61}}}
(2) {{{2c + 5b = 233}}}
Multiply both sides of (1) by {{{2}}} and
subtract (1) from (2)
(2) {{{2c + 5b = 233}}}
(1) {{{-2c - 2b = 122}}}
{{{3b = 111}}}
{{{b = 37}}}
and, since
{{{c + b = 61}}}
{{{c + 37 = 61}}}
{{{c = 24}}}
There are 24 coins and 37 bills