Question 312650
{{{3/(x^2-x) - (2x-1)/(x^2+2x-3)=3/(x(x-1))-(2x-1)/((x+3)(x-1))}}}
Multiply the first term by {{{(x+3)/(x+3)}}} and the second term by {{{x/x}}}to get a common denominator.
{{{3/(x^2-x) - (2x-1)/(x^2+2x-3)=(3(x+3))/(x(x-1)(x+3))-(x(2x-1))/(x(x+3)(x-1))}}}
{{{3/(x^2-x) - (2x-1)/(x^2+2x-3)=(3x+9-2x^2+x)/(x(x-1)(x+3))}}}
{{{3/(x^2-x) - (2x-1)/(x^2+2x-3)=(-2x^2+4x+9)/(x(x-1)(x+3))}}}