Question 312702
The perimeter of a rectangle is,
{{{P=2*(L+W)=156}}}
{{{L+W=78}}}
The length is 6 cm longer than the width,
{{{L=W+6}}}
Substitute and solve,
{{{(W+6)+W=78}}}
{{{2W=72}}}
{{{highlight(W=36)}}}
Then from above,
{{{L=W+6}}}
{{{highlight(L=42)}}}