Question 312706
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Area is length times width:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{6}\ \times\ \sqrt{3}\ =\ \sqrt{6\,\cdot\,3}\ =\ \sqrt{18}\ =\ \sqrt{9\,\cdot\,2}\ =\ \sqrt{9}\ \times\ \sqrt{2}\ =\ 3\sqrt{2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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