Question 312663
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The area of a rectangle is length times width.  If you let *[tex \Large x] represent the width, then *[tex \Large x\ +\ 4] has to represent the length.  Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(x\ +\ 4)\ =\ 144]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 4x\ -\ 144\ =\ 0]


Just solve the quadratic.  You will need to use the quadratic formula.  Discard the negative root because you are looking for a positive measure of length.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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