Question 312531
LET X & X+1 BE THE 2 NUMBERS.
41=X^2+(X+1)^2
41=X^2+X^2+2X+1
2X^2+2X+1-41=0
2X^2+2X-40=0
2(X^2+X+420)=0
2(X+5)(X-4)=0
X-4=0
X=4 ANS FOR THE SMALLER NUMBER.
PROOF:
41=4^2+(4+1)^2
41=16+5^2
41=16+25
41=41