Question 312452
If it's possible it's an easy way to find the zeros of the function, that is, the x locations where the function crosses the x-axis.
There may be 0,1, or at most 2 solutions to a quadratic equation as shown below in my three examples. 
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{{{ drawing( 300, 300, -8, 8, -6, 10,grid(1),circle(-3,0,.3),circle(sqrt(2),0,.3),circle(-sqrt(2),0,.3),graph( 300, 300, -8, 8, -6, 10, (x+3)^2, (x)^2-2, (x-4)^2+2)) }}}
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Red-{{{f(x)=(x+3)^2}}}, {{{x=-3}}}
Green-{{{g(x)=x^2-2}}}, {{{x=-sqrt(2)}}} and {{{x=sqrt(2)}}}
Blue-{{{h(x)=x^2-8x+18}}}, No real solutions, doesn't cross the x-axis.