Question 312542
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I've already shown you twice today how to find the vertex of a parabola which equation is in vertex form, so I'm going to assume that you can handle that part.


Let *[tex \LARGE a] be the *[tex \LARGE x]-coordinate of the parabola vertex.  Then an equation of the axis of symmetry is *[tex \LARGE x\ =\ a].



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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