Question 312541
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Missed it by <b><i>that</i></b> much!


The vertex form of a parabola with vertex at *[tex \Large (h,k)] is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ 4p(x\ -\ h)^2\ +\ k]


Hence, your vertex is at *[tex \Large (4,-9)]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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