Question 312510
{{{(y^2-8y+15)/(y^2+4y-45)=((y-5)(y-3))/((y+9)(y-5))}}}
{{{(y^2-8y+15)/(y^2+4y-45)=(cross(y-5)(y-3))/((y+9)cross(y-5))}}}
{{{(y^2-8y+15)/(y^2+4y-45)=(y-3)/(y+9)}}}