Question 312465
{{{f(x)=2x-cos(x)+1=0}}}
I used Newton's method and found {{{highlight(x=0)}}} as a solution which is verified graphically below.
{{{ graph( 300, 300, -2, 2, -10, 10, 2x-cos(x)+1) }}} 
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{{{f(x)=2x-cos(x)+1=1}}}
{{{f(x)=2x-cos(x)=0}}}
I solved this one by hand using an EXCEL spreadsheet.
{{{ graph( 300, 300, -1, 2, -10, 10, 2x-cos(x)) }}} 
{{{highlight(x=0.450199)}}}