Question 312499
You will need to use the formula 4.9t2 + v0t = s, where t is the time in seconds, v0 is the initial velocity, and s is the distance in meters. 
Approximately how far will an object fall in 13 seconds (t) when thrown downward at an initial velocity of 10 meters per second (v0) from a plane?
.
Starting with the provided equation: (I think you forgot the negative sign in front of the 4.9)
{{{ -4.9t^2 + v0t = s }}}
Notice, it said "thrown downward" so Vo will be -10 meters per second.
Plug in the given info:
{{{ -4.9(13)^2 + (-10)(13) = s }}}
{{{ -4.9(169) + (-10)(13) = s }}}
{{{ -828.1 - 130 = s }}}
{{{ -958.1 = s }}} (meters)
.
That is, it will fall 958.1 meters