Question 312491
Quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{y=(1/2)x^2
a=1/2
b=0
c=0
{{{x = (0 +- sqrt( 0-4*(1/2)*0 ))/(2*(1/2)) }}}
{{{x = (0 +- 0 )/(1) }}}
{{{x=0}}}
(0,0) is the first point. 
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When {{{ x=0 +- 1 }}} , {{{ y=(1/2)(1)^2=1/2}}}
When {{{ x=0 +- 2}}}, {{{ y=(1/2)(2)^2=2}}}
When {{{ x=0 +- 3}}}, {{{ y=(1/2)(3)^2=9/2}}}

Plot the ordered pairs.
{{{ drawing( 300, 300, -5, 5, -2, 5, grid(1),
circle(0,0,.2),
circle(1,1/2,.2),
circle(2,2,.2),
circle(3,9/2,.2),
circle(-1,1/2,.2),
circle(-2,2,.2),
circle(-3,9/2,.2),
graph( 300, 300, -5, 5, -2, 5, 0)) }}} 
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Now connect the points with a parabola. 
{{{ drawing( 300, 300, -5, 5, -2, 5, grid(1),
circle(0,0,.2),
circle(1,1/2,.2),
circle(2,2,.2),
circle(3,9/2,.2),
circle(-1,1/2,.2),
circle(-2,2,.2),
circle(-3,9/2,.2),
graph( 300, 300, -5, 5, -2, 5, (1/2)x^2)) }}}