Question 36361
{{{((x^2 -8x+15)/(3x-15))/(x^2-3x))}}}
First factor the numerator and factor out the 3in the denominator
{{{((x-3)(x-5)/(3(x-5)))/(x^2-3x)}}}
Now cancel the x-5 in both the numerator anddenominator;
{{{((x-3)/3)/(x^2-3x)}}}
factor out the x in the denominator;
{{{((x-3)/3)/(x(x-3))}}}
When we divide fractions, we multiply the first by the reciprocal of the second;
{{{(x-3)/3}}} * {{{1/x(x-3)}}};
cross cancel x-3;
{{{1/3x}}}
=)