Question 312297
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FOIL it!


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 12a^2\ -\ 5a\ -\ 2\ =\ 5]


Standard Form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 12a^2\ -\ 5a\ -\ 7\ =\ 0]


Now just factor it...



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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