Question 312236
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Put it in standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 4x\ -\ 1\ =\ 0]


This one doesn't factor, so the easiest thing to do is to use the quadratic formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-(-4)\ \pm\ \sqrt{(-4)^2\ -\ 4(1)(-1)}}{2(1)} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{4\ \pm\ \sqrt{20}}{2} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{4\ \pm\ 2\sqrt{5}}{2} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = 2\ \pm\ \sqrt{5}]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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