Question 312210
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A circle centered at *[tex \Large \left(h,k\right)] with radius *[tex \Large r] is described by the equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ h\right)^2\ +\ \left(y\ -\ k\right)^2\ =\ r^2]


Re-write your equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(x\ -\ 0\right)^2\ +\ \left(y\ -\ (-5)\right)^2\ =\ \left(\sqrt{17}\right)^2]


And you can determine your center and radius by inspection.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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