Question 36422
 (x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2)

 (x^2-6x+8) can be written as (x-4)(x-2)
 (x^2+3x-28) can be written as (x+7)(x-4)
 (x^2+6x-7) can be written as (x+7)(x-1)
 (x^2-3x+2) can be written as (x-2)(x-1)


((x-4)(x-2))/((x+7)(x-4)) *  ((x+7)(x-1))/((x-2)(x-1))


Writting the numerator and denominatiors separately


(x-4)(x-2)(x+7)(x-1)
---------------------
(x+7)(x-4)(x-2)(x-1)

Cancelling out the common terms you get 1


Answer is 1