Question 311987
{{{((8x^3*y^2*z^2)*3x^2)/(y^3*z^4)=((8*3)/3)*x^(3+2)*y^(2-3)*z^(2-4)}}}

{{{((8x^3*y^2*z^2)*3x^2)/(y^3*z^4)=((8*cross(3))/cross(3))*x^(5)*y^(-1)*z^(-2)}}}
{{{((8x^3*y^2*z^2)*3x^2)/(y^3*z^4)=8*x^(5)/(y*z^(2))}}}