Question 311991
First plot, {{{y=x^2-12x+36}}}

{{{ graph( 300, 300, -10, 10, -10, 10, x^2-12x+36) }}}
Now choose a point not on the parabola. 
(0,0) is an available point. 
Test the inequality.
If the point satisfies the inequality, it's in the solution region.
If it doesn't, it's not in the solution region".
(0,0)
{{{0<0-12(0)+36}}}
{{{36>0}}}
True, so (0,0) is in the solution region. 
Shade the region containing (0,0).
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.
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*[invoke plot_any_inequality "y < x^2-12x+36", -10, 10, -10, 10, 300, 300]