Question 310542
That's easy:

loga2+4loga y-2loga z

Solution;
Apply the laws of logarithms;
loga2+log(a)y^4-log(a)z^2
log(a)(2*y^4/z^2)
log(a)(2y^4/z^2) 

Final answer: log(a)(2y^4/z^2)