Question 310861
Given that log2=0.0301 and log5=0.699
then;
log 8/125= log2^3/log5^3
         = 3log2/3log5
         = (3log2)-(3log5)
         =3(0.0301)-3(0.699)
         =0.903-2.097
log8/125=-1.194