Question 36394
Discriminant = (b^2 - 4ac) for ax^2+bx+c
Here a = 4/3, b=-2 and c = 3/4
b^2 - 4ac = 4 - 4 = 0
If b^2 - 4ac =0, there is only one real solution.
If b^2 - 4ac > 0, both the roots are real.
If b^2 - 4ac < 0, both the roots are non-real complex.
Here the discriminant is 0; so there is only one real solution of the given equation.