Question 311687
let the numbers be x, x+2, x+4

square of the third= (x+4)^2
square of the second = (x+2)^2

.
(x+4)2 = (x+2)^2 +28
x^2 +8x +64= X^2+4x+4 +28
8x-4x=-64+32
4x= -32
x=-8
-8. -6, -4