Question 311637
You cannot "solve" this -- you can, however, factor it.
If you see:
{{{ x^3-27 }}}
This is a "special case" because you can rewrite it as:
{{{ x^3-3^3 }}}
Now, you have a "difference of cubes".  It should automatically bring to mind:
{{{ a^3–b^3 = (a – b)(a^2 + ab + b^2) }}}
In your case:
a is x
b is 3
giving you:
{{{ x^3-3^3 = (x-3)(x^2 + 3x + 3^2) }}}
{{{ x^3-3^3 = (x-3)(x^2 + 3x + 9) }}}