<PRE><B>Question 4714</B>
I think there is an error in the previously posted solution.


Let W = Width of the rectangle
L = Length of the rectangle


Perimeter:  2W + 2L = 22
2nd Equation: L = 2W - 4


Solve by substituting L from the second equation into the first equation:
2W + 2(_____) = 22
2W + 2(2W -4) = 22
2W + 4W - 8 = 22
2W = 30
W= 5


Substitute into second equation:
L = 2W - 4
L = 2(5) - 4
L = 10 - 4 = 6


Check:  
P = 2W + 2L
P = 2(5) + 2(6) 
P = 10 + 12 = 22

AND
L = 2W - 4
6 = 2(5) - 4
6 =  10 - 4


R^2 at SCC
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