Question 311591
2x^2-5x=-7
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2x^2-5x+7 = 0
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2x^2-7x+2x+7 = 0
x(2x-7)+(2x+7) = 0
(2x-7)(x+1) = 0
x = 7/2 or x = -1
need the solution set= {7/2 , -1}

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Cheers,
Stan H.
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