Question 311314
Steve can tape and mud the drywall of a room in 6 hours.
 Mike can do it in 4 hours.
 Mike joins Steve an hour after Steve starts and together they worked finishing the job.
 How long did each one work?
:
Let t = Mikes working time
then
(t+1) = Steve's working time
:
Let the completed job = 1
:
A shared work equation
{{{(t+1)/6}}} + {{{t/4}}} = 1
multiply equation by 12, results
2(t+1) + 3t = 12
:
2t + 2 + 3t = 12
:
2t + 3t = 12 - 2
:
5t = 10
t = {{{10/5}}}
t = 2 hrs is Mike's working time
and
2 + 1 = 3 hrs is Steve's working time
:
:
Check solution
{{{3/6}}} + {{{2/4}}} = 1