Question 311103
Solve 8x^2 + 2x - 3 = 0 Reduce fractions to lowest terms.

a) x = 3/4 or x = -3/4
b) x = 2 or x = -3
c) x = 1/2 or x = -3/4
d) x = 3/4 or x = -1/2

Okay, so for this all we need is a bit of factoring!
so we should first multiply 8 by -3. The answer is -24. Then, all you have to do is find the two factors of that number that will create the middle number. Those numbers are -4 and 6. So now it is time for equations!
(8x^2-4x) (6x-3) Now take out the common factors.
4x(2x-1) 3(2x-1) Now put those all together
(4x+3)(2x-1)=0   Now you have to find the number that makes at least one of the expressions equal to ZERO
4x+3=0     
4x=-3 
x=-3/4
and for the other equation:   
2x-1=0
2x=1                                  
x=1/2
So the answer is C.
I hope this helped!