Question 36364
find two consecutive even integers whose product is 
288
let x and x+2 are the two even intergers

 therefore, x (x+2) = 288  ( the product of two integers)
              x^2 +2x =288
              x^2+2x-288=0
             
x^2  + 18x -16x -288 =0

x (x+18)-16(x+18)=0

x =18 and x =16 are the the integers