Question 311431
(2y - 4)( 2y + 3) = 0

did u realize what this foils in to? 4y^2-y-12=0  so this would be incorrect
id simply do this:
{{{4y^2=12}}}
divide by 4
{{{y^2=3}}}
sqrt each side
{{{y=sqrt(3)}}}
{{{y=-sqrt(3)}}}