Question 311365
Add or subtract as indicated 7b+6/6b-36 - b+2/b-6
:
{{{(7b+6)/(6b-36)}}} - {{{(b+2)/(b-6)}}}
Factor out 6 in 1st denominator, results:
{{{(7b+6)/(6(b-6))}}} - {{{(b+2)/(b-6)}}}
the common denominator is 6(b-6), therefore
{{{((7b+6)-6(b+2))/6(b-6)}}} = {{{(7b + 6 - 6b - 12)/6(b-6)}}}
Group like terms
{{{(7b - 6b + 6 - 12)/6(b-6)}}} = {{{(b - 6)/6(b-6)}}}
Cancel the (b-6)'s and you have
{{{1/6}}}