Question 36320
The area under the curve:{{{y = e^2x}}} between x = 2 and x = 3 is given by taking the integral{{{integral(ydx)}}} evaluated from x = 2 to x = 3
I don't know how to show the integral sign, so I'll use S 
{{{S(e^(2x))dx = e^(2x)/2}}} from x=2 to x=3
{{{A = (e^(2*3))/2 - (e^(2*2))/2}}}
{{{A = (e^6 - e^4)/2}}}
{{{A = 384.831/2}}}
{{{A = 174.4155}}}