Question 311255
Here, let x be the tens digit and y be the ones digit.
So we have
x + y = 11 and x = y + 5
We can substitute y + 5 for x in the first equation and get
(y + 5) + y = 11
2y + 5 = 11
2y = 6
y = 3 and thus
x = 8
The number is 83.