Question 311290
{{{(x+3)^2+27x+60=0}}}
{{{(x+3)^2+27(x+3)+60-81=0}}}
{{{(x+3)^2+27(x+3)-21=0}}}
Let {{{u=x+3}}}
{{{u^2+27u-21=0}}}
Use the quadratic formula,
{{{u = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{u = (-27 +- sqrt( 27^2-4*1*(-21) ))/(2*1) }}}
{{{u = (-27 +- sqrt( 729+84 ))/(2) }}}
{{{u = (-27 +- sqrt( 813 ))/(2) }}}
{{{x+3 = (-27 +- sqrt( 813 ))/(2) }}}
{{{x = (-33 +- sqrt( 813 ))/(2) }}}or approximately,
{{{x=-30.8}}} and {{{x=-2.2}}}
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 {{{ graph( 300, 300, -45, 5, -50, 50, (x+3)^2+27x+60) }}}