Question 36332
find {{{f^-1(x)}}} if {{{f(x) =2x-1}}}
{{{f(x) =2x-1}}} original
{{{y=2x-1}}} substitue y-values for f(x)
{{{x=2y-1}}} to find inverse, switch the 'y' and 'x'
{{{x+1=2y}}} add 1 to each side
{{{(x+1)/2=y}}} divide by 2 to get 'y' by itself
{{{f^-1(x)=(x+1)/2}}}