Question 311144
Perpendicular lines have negative reciprocal slopes.
{{{m1*m2=-1}}}
{{{(5/2)m2=-1}}}
{{{m2=-2/5}}}
Use the point-slope form of a line,
{{{y-yp=m(x-xp)}}}
{{{y-(-8)=(-2/5)(x-5)}}}
{{{y+8=-(2/5)x+2}}}
{{{highlight_green(y=-(2/5)x-6)}}}
{{{ drawing( 300,300, -5, 10, -10, 5, grid(1),circle(5,-8,.25),graph( 300,300, -5, 10, -10, 5, -(2/5)x-6, (5/2)x+4) )}}}